Vector Is Not A Template

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Vector in the function signature. Commented jun 24, 2020 at 9:39. You have to do this because vector is defined in the std. You're getting the errors because u64 is not defined at that point. This however is rather unwielding.

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You have to do this because vector is defined in the std. Everywhere qualify it by std:: Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be. The same result can however be achieved by simply including in the header file, this way you.

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Vector is a template, not a type, you need the template argument list e.g. This however is rather unwielding. Anyway define a type instead of a macro. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Commented jun 24, 2020 at 9:39.

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Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. You're getting the errors because u64 is not defined at that point..

Vector Is Not A Template

Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be. The code is parsed in the order it appears. Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.</p> If we start in node.h, early on, it includes.

Vector Is Not A Template - Vector is a template, not a type, you need the template argument list e.g. Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be. As some commenters have noted, you have circular references. The type of the vector you want to create is of the same kind of iter. Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.</p> Anyway define a type instead of a macro.

Since you're passing a pointer to a vector you need to. You have to do this because vector is defined in the std. Vector is a template, not a type, you need the template argument list e.g. It is not true that the type is not known. Vector in the function signature.

You Have To Do This Because Vector Is Defined In The Std.

The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. You're getting the errors because u64 is not defined at that point. Since you're passing a pointer to a vector you need to. This however is rather unwielding.

Template Void Some_Func( Std::vector<T,A> Const& Vec ) { } The Second Argument Is The Allocator, And In Some Advanced Usage Of Std::vector It Will Not Be.

Vector is a template, not a type, you need the template argument list e.g. Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.

Anyway Define A Type Instead Of A Macro.

Just get iter underlying type either using decltype or using iterator. Anyway define a type instead of a macro. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. Everywhere qualify it by std::

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As some commenters have noted, you have circular references. It is not true that the type is not known. The code is parsed in the order it appears. Commented jun 24, 2020 at 9:39.